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Programming interviews in C++ approximately timber
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Additional resources for A collection of Tree Programming Interview Questions Solved in C++
Starting from the root, the tree is recursively traversed from top to bottom and at each level the search chooses the subtree, which has separation keys on both sides of the search value. The search within a node can be linear or binary. Insertion To insert a new key, search the tree to find the leaf node, where the new key should be added: If the node contains fewer than, then there is room for the new element, which can be inserted by following the order. Otherwise if the node is full and it must be split into two nodes: The median element is selected among the leaf's elements and the new element.
A question for the interested reader could be, whether or not this one is the optimal complexity. 12 Printing a zig-zag traversal Solution A Zig-Zag traversal is implemented by using two stacks which are swapped at every level. During the visit of currentLevel all children are inserted in the nextLevel stack. To be considered: a Boolean value is maintained for determining the direction of a visit (either left to right, or right to left) and this direction in reversed at every cycle. When a currentLevel stack is empty, then it is swapped with nextLevel.
When data is inserted or removed from a node, its number of children nodes changes and therefore internal nodes may be joined or split for guaranteeing that they don’t exceed the range. Each internal node of a B-tree will contain a number of sorted keys. Keys act as separation values which divide a tree into subtrees as explained in the image below. Therefore is the minimum branching factor for the tree. The factor of 2 will guarantee that nodes can be split or combined. If an internal node has keys, then adding a key to that node can be accomplished by splitting the key node into two key nodes and by adding the key to the parent.
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